(x-4)^2+(x+2)(x+1)=9

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Solution for (x-4)^2+(x+2)(x+1)=9 equation: 



(x-4)^2+(x+2)(x+1)=9

We move all terms to the left:

(x-4)^2+(x+2)(x+1)-(9)=0

We multiply parentheses ..

(+x^2+x+2x+2)+(x-4)^2-9=0

We get rid of parentheses

x^2+x+2x+(x-4)^2+2-9=0

We add all the numbers together, and all the variables

x^2+3x+(x-4)^2-7=0

We move all terms containing x to the left, all other terms to the right

x^2+3x+(x-4)^2=7

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